Ответ:

а) x=4, f(4)=9

б) x=5, f(5)=15

в) x=25, f(25)=29

г) x=0, f(0)=1 x=0, f(0)=1x=0, f(0)=1

д) x=\infty, f(\infty)=\infty

е) x=0, f(0)=20

ж) x=\infty, f(\infty)=\infty

з) x=4, x=8, f(4)=f(8)=22

и) x=1, f(1)=28

к) x=3, f(3)=46

л) При a \in [0; 2) \quad f_{\text{max}} = f(a) = -a^2 + 4a + 10

При a \in [2; \infty) \quad f_{\text{max}} = f(2) = 14

м) При a \leq 0{,}4 \quad f_{\text{max}} = f(0) = 3

При a > 0{,}4 \quad f_{\text{max}} = f(10) = 3

н) При y \geq 0 \quad f_{\text{max}} = f(y) = 0 \\ При y < 0 \quad f_{\text{max}} = f(0) = -y^2

о) При y \leq 0 \quad f_{\text{max}} = f(-5y) = 24y^2 + 2

При y > 0 \quad f_{\text{max}} = f(0) = -y^2 + 2

п) При y \leq 1{,}2 \quad f_{\text{max}} = f(5) = -25 + 40y + 17y^2 - y^7

При y \in (1{,}2; 2{,}5] \quad f_{\text{max}} = f(4y) = 33y^2 - y^7

При y > 2{,}5 \quad f_{\text{max}} = f(10) = -100 + 80y + 17y^2 - y^7

р) При x \geq 0 \quad f_{\text{max}} = f(3x) = 8x^2

При x < 0 \quad f_{\text{max}} = f(0) = -x^2

с) При k \in (-\infty; 0) \cup [0; 5; \infty) \quad f_{\text{max}} = f(2) = -4k^2 + 4k + y^2 - y^{42}

При k \in \left[\frac{1}{8}; 0{,}5\right) \quad f_{\text{max}} = f\left(\frac{1}{k}\right) = 1 + y^2 - y^{42}

При k \in (0; \frac{1}{8}) \quad f_{\text{max}} = f(8) = -64k^2 + 16k + y^2 - y^{42}

При k = 0 \quad f_{\text{max}} = y^2 - y^{42}

т) x = \frac{\psi}{2}, \quad f_{\text{max}} = \frac{1}{4}\psi^4 + 11\psi^{7e} + \pi^\psi